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题目

Design a HashMap without using any built-in hash table libraries.

To be specific, your design should include these functions:

  • put(key, value) : Insert a (key, value) pair into the HashMap. If the value already exists in the HashMap, update the value.
  • get(key): Returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key.
  • remove(key) : Remove the mapping for the value key if this map contains the mapping for the key.

Example:

MyHashMap hashMap = new MyHashMap();
hashMap.put(1, 1);          
hashMap.put(2, 2);         
hashMap.get(1);            // returns 1
hashMap.get(3);            // returns -1 (not found)
hashMap.put(2, 1);          // update the existing value
hashMap.get(2);            // returns 1 
hashMap.remove(2);          // remove the mapping for 2
hashMap.get(2);            // returns -1 (not found)

Note:

  • All keys and values will be in the range of [0, 1000000].
  • The number of operations will be in the range of [1, 10000].
  • Please do not use the built-in HashMap library.

题目大意

不使用任何内建的哈希表库设计一个哈希映射具体地说,你的设计应该包含以下的功能:

  • put(key, value):向哈希映射中插入(键,值)的数值对。如果键对应的值已经存在,更新这个值。
  • get(key):返回给定的键所对应的值,如果映射中不包含这个键,返回 -1。
  • remove(key):如果映射中存在这个键,删除这个数值对。

注意:

  • 所有的值都在 [1, 1000000] 的范围内。
  • 操作的总数目在 [1, 10000] 范围内。
  • 不要使用内建的哈希库。

解题思路

  • 简单题,设计一个 hashmap 的数据结构,要求有 put(key, value)get(key)remove(key),这 3 个方法。设计一个 map 主要需要处理哈希冲突,一般都是链表法解决冲突。








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