Let's meet Friendly Language Uncle For Life #94
Description
The example worked in interpreter but not when I write in a .py file.
from __future__ import barry_as_FLUFL
import sys
print(sys.version)
"Ruby" != "Python" #This is OKfrom __future__ import barry_as_FLUFL
import sys
print(sys.version)
"Ruby" <> "Python" #But this raise a exceptionoutput 1:
3.6.5 |Anaconda, Inc.| (default, Mar 29 2018, 13:32:41) [MSC v.1900 64 bit (AMD64)]output 2:
File "test.py", line 4
"Ruby" <> "Python"
^
SyntaxError: invalid syntax