diff --git a/02-strings/02_AnagramCheck.java b/02-strings/02_AnagramCheck.java
new file mode 100644
index 0000000..650b5c2
--- /dev/null
+++ b/02-strings/02_AnagramCheck.java
@@ -0,0 +1,34 @@
+// Problem: Anagram Check
+// Author: Ataubl (codeByunique)
+
+import java.util.Arrays;
+
+class AnagramCheck {
+ public static void main(String[] args) {
+ String str1 = "listen";
+ String str2 = "silent";
+
+ if (areAnagrams(str1, str2)) {
+ System.out.println(str1 + " and " + str2 + " are anagrams.");
+ } else {
+ System.out.println(str1 + " and " + str2 + " are not anagrams.");
+ }
+ }
+
+ public static boolean areAnagrams(String s1, String s2) {
+ // Step 1: Remove whitespace & convert to lowercase
+ s1 = s1.replaceAll("\\s", "").toLowerCase();
+ s2 = s2.replaceAll("\\s", "").toLowerCase();
+
+ // Step 2: If lengths differ, can't be anagrams
+ if (s1.length() != s2.length()) return false;
+
+ // Step 3: Sort and compare
+ char[] arr1 = s1.toCharArray();
+ char[] arr2 = s2.toCharArray();
+ Arrays.sort(arr1);
+ Arrays.sort(arr2);
+
+ return Arrays.equals(arr1, arr2);
+ }
+}
diff --git a/02-strings/README.md b/02-strings/README.md
index e75fde4..8d09378 100644
--- a/02-strings/README.md
+++ b/02-strings/README.md
@@ -23,3 +23,24 @@ Use two pointers (start and end), and check if characters match while moving inw
**Time Complexity:** O(n)
**Space Complexity:** O(1)
+
+---
+
+### 🔤 Anagram Check
+
+**Problem:**
+Check whether two strings are anagrams of each other.
+
+**Input:** "listen", "silent"
+**Output:** true
+**Explanation:** Both have same letters in different order
+
+**Approach:**
+- Clean the strings (remove spaces and convert to lowercase)
+- Sort both strings
+- Compare the sorted versions
+
+**Time Complexity:** O(n log n)
+**Space Complexity:** O(n)
+
+---
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