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README.md

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@@ -8,6 +8,7 @@ _If you like this project, please leave me a star._ ★
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| # | Title | Solutions | Video | Difficulty | Tag
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|-----|----------------|---------------|--------|-------------|-------------
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|1829|[Maximum XOR for Each Query](https://leetcode.com/problems/maximum-xor-for-each-query/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1829.java) ||Medium|Bit Manipulation|
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|1828|[Queries on Number of Points Inside a Circle](https://leetcode.com/problems/queries-on-number-of-points-inside-a-circle/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1828.java) ||Medium|Math|
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|1827|[Minimum Operations to Make the Array Increasing](https://leetcode.com/problems/minimum-operations-to-make-the-array-increasing/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1827.java) ||Easy|Array, Greedy|
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|1823|[Find the Winner of the Circular Game](https://leetcode.com/problems/find-the-winner-of-the-circular-game/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1823.java) ||Medium|Array|
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package com.fishercoder.solutions;
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public class _1829 {
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public static class Solution1 {
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public int[] getMaximumXor(int[] nums, int maximumBit) {
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int[] result = new int[nums.length];
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long[] xOr = new long[nums.length];
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xOr[0] = nums[0];
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for (int i = 1; i < nums.length; i++) {
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xOr[i] ^= xOr[i - 1] ^ nums[i];
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}
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long maxNum = (long) Math.pow(2, maximumBit) - 1;
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for (int i = 0; i < nums.length; i++) {
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result[nums.length - i - 1] = (int) (maxNum ^ xOr[i]);
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}
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return result;
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}
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}
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}

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