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update 91
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src/main/java/com/fishercoder/solutions/_91.java

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package com.fishercoder.solutions;
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import java.util.HashMap;
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import java.util.Map;
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public class _91 {
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/**
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* Credit: https://discuss.leetcode.com/topic/35840/java-clean-dp-solution-with-explanation
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return dp[s.length()];
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}
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}
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public static class Solution2 {
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/**credit: https://leetcode.com/problems/decode-ways/solution/
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* Approach 1: Recursive Approach with Memoization
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*
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* The actual code goes from the right most character to the left side to build out the dp cache map.
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* And this HashMap uses index as its key instead of a substring.
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* */
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public int numDecodings(String s) {
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return dp(new HashMap<>(), s, 0);
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}
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private int dp(Map<Integer, Integer> cache, String s, int index) {
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if (cache.containsKey(index)) {
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return cache.get(index);
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}
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if (index == s.length()) {
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//this means we reached the end of the string, so return 1 as success
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return 1;
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}
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if (s.charAt(index) == '0') {
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//this means this string cannot be decoded
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return 0;
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}
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if (index == s.length() - 1) {
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return 1;
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}
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int ways = dp(cache, s, index + 1);
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if (Integer.parseInt(s.substring(index, index + 2)) <= 26) {
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ways += dp(cache, s, index + 2);
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}
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cache.put(index, ways);
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return cache.get(index);
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}
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}
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}

src/test/java/com/fishercoder/_91Test.java

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public class _91Test {
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private static _91.Solution1 solution1;
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private static _91.Solution2 solution2;
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@BeforeClass
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public static void setup() {
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solution1 = new _91.Solution1();
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solution2 = new _91.Solution2();
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}
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@Test
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public void test1() {
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assertEquals(2, solution1.numDecodings("12"));
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assertEquals(2, solution2.numDecodings("12"));
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}
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@Test
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public void test2() {
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assertEquals(1, solution1.numDecodings("10"));
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assertEquals(1, solution2.numDecodings("10"));
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}
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}

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