Consider the following snippet:

const foo = ['a', 'b', 'c']; // type: string[]
const bar = foo[5]; // type: string, value: undefined

// Passes the rule
if (foo[5]) {
  console.log(foo[5]);
}

// Fails the rule
if (bar) {
  console.log(bar);
}

Thanks to @Retsam's work on #1534, the first example passes the linter, however as the author mentions in their PR, it doesn't handle less trivial cases, such as storing the value in a variable (which is very common when you want to use the value being tested in the body of the if).

I realize that supporting this (and other advanced) cases might be a lift. In the meantime, or alternatively, any thoughts on an option to entirely ignore arrays? In the current state, I don't believe there is a way to make the second example above pass the linter without disabling the rule or getting rid of the variable.
I believe such option was mentioned in #1544, for reference.

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