LeetCode in Kotlin

72. Edit Distance

Hard

Given two strings word1 and word2, return the minimum number of operations required to convert word1 to word2.

You have the following three operations permitted on a word:

• Insert a character
• Delete a character
• Replace a character

Example 1:

Input: word1 = “horse”, word2 = “ros”

Output: 3

Explanation:

horse -> rorse (replace ‘h’ with ‘r’)

rorse -> rose (remove ‘r’)

rose -> ros (remove ‘e’)

Example 2:

Input: word1 = “intention”, word2 = “execution”

Output: 5

Explanation:

intention -> inention (remove ‘t’)

inention -> enention (replace ‘i’ with ‘e’)

enention -> exention (replace ‘n’ with ‘x’)

exention -> exection (replace ‘n’ with ‘c’)

exection -> execution (insert ‘u’)

Constraints:

• 0 <= word1.length, word2.length <= 500
• word1 and word2 consist of lowercase English letters.

Solution

class Solution {
    fun minDistance(word1: String, word2: String): Int {
        val n1 = word1.length
        val n2 = word2.length
        if (n2 > n1) {
            return minDistance(word2, word1)
        }
        val dp = IntArray(n2 + 1)
        for (j in 0..n2) {
            dp[j] = j
        }
        for (i in 1..n1) {
            var pre = dp[0]
            dp[0] = i
            for (j in 1..n2) {
                val tmp = dp[j]
                dp[j] = if (word1[i - 1] != word2[j - 1]) 1 + Math.min(pre, Math.min(dp[j], dp[j - 1])) else pre
                pre = tmp
            }
        }
        return dp[n2]
    }
}

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