LeetCode in Kotlin

164. Maximum Gap

Hard

Given an integer array nums, return the maximum difference between two successive elements in its sorted form. If the array contains less than two elements, return 0.

You must write an algorithm that runs in linear time and uses linear extra space.

Example 1:

Input: nums = [3,6,9,1]

Output: 3

Explanation: The sorted form of the array is [1,3,6,9], either (3,6) or (6,9) has the maximum difference 3.

Example 2:

Input: nums = [10]

Output: 0

Explanation: The array contains less than 2 elements, therefore return 0.

Constraints:

• 1 <= nums.length <= 105
• 0 <= nums[i] <= 109

Solution

class Solution {
    fun maximumGap(nums: IntArray): Int {
        if (nums.size < 2) {
            return 0
        }
        var ret = Int.MIN_VALUE
        nums.sort()
        for (i in 0 until nums.size - 1) {
            if (nums[i + 1] - nums[i] > ret) {
                ret = nums[i + 1] - nums[i]
            }
        }
        return ret
    }
}

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