LeetCode in Kotlin

3523. Make Array Non-decreasing

Medium

You are given an integer array nums. In one operation, you can select a subarray and replace it with a single element equal to its maximum value.

Return the maximum possible size of the array after performing zero or more operations such that the resulting array is non-decreasing.

A subarray is a contiguous non-empty sequence of elements within an array.

Example 1:

Input: nums = [4,2,5,3,5]

Output: 3

Explanation:

One way to achieve the maximum size is:

1. Replace subarray nums[1..2] = [2, 5] with 5 → [4, 5, 3, 5].
2. Replace subarray nums[2..3] = [3, 5] with 5 → [4, 5, 5].

The final array [4, 5, 5] is non-decreasing with size 3.

Example 2:

Input: nums = [1,2,3]

Output: 3

Explanation:

No operation is needed as the array [1,2,3] is already non-decreasing.

Constraints:

• 1 <= nums.length <= 2 * 105
• 1 <= nums[i] <= 2 * 105

Solution

class Solution {
    fun maximumPossibleSize(nums: IntArray): Int {
        var res = 0
        var prev = Int.Companion.MIN_VALUE
        for (x in nums) {
            if (x >= prev) {
                res++
                prev = x
            }
        }
        return res
    }
}

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