LeetCode in Net

92. Reverse Linked List II

Medium

Given the head of a singly linked list and two integers left and right where left <= right, reverse the nodes of the list from position left to position right, and return the reversed list.

Example 1:

Input: head = [1,2,3,4,5], left = 2, right = 4

Output: [1,4,3,2,5]

Example 2:

Input: head = [5], left = 1, right = 1

Output: [5]

Constraints:

• The number of nodes in the list is n.
• 1 <= n <= 500
• -500 <= Node.val <= 500
• 1 <= left <= right <= n

Follow up: Could you do it in one pass?

Solution

using LeetCodeNet.Com_github_leetcode;

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     public int val;
 *     public ListNode next;
 *     public ListNode(int val=0, ListNode next=null) {
 *         this.val = val;
 *         this.next = next;
 *     }
 * }
 */
public class Solution {
    public ListNode ReverseBetween(ListNode head, int left, int right) {
        if (head == null || left == right) {
            return head;
        }
        ListNode dummy = new ListNode(0, head);
        ListNode prev = dummy;
        for (int i = 0; i < left - 1; i++) {
            prev = prev.next;
        }
        ListNode curr = prev.next;
        for (int i = 0; i < right - left; i++) {
            ListNode next = curr.next;
            curr.next = next.next;
            next.next = prev.next;
            prev.next = next;
        }
        return dummy.next;
    }
}

This site is open source. Improve this page.