LeetCode in Net

129. Sum Root to Leaf Numbers

Medium

You are given the root of a binary tree containing digits from 0 to 9 only.

Each root-to-leaf path in the tree represents a number.

• For example, the root-to-leaf path 1 -> 2 -> 3 represents the number 123.

Return the total sum of all root-to-leaf numbers. Test cases are generated so that the answer will fit in a 32-bit integer.

A leaf node is a node with no children.

Example 1:

Input: root = [1,2,3]

Output: 25

Explanation: The root-to-leaf path 1->2 represents the number 12. The root-to-leaf path 1->3 represents the number 13. Therefore, sum = 12 + 13 = 25.

Example 2:

Input: root = [4,9,0,5,1]

Output: 1026

Explanation: The root-to-leaf path 4->9->5 represents the number 495. The root-to-leaf path 4->9->1 represents the number 491. The root-to-leaf path 4->0 represents the number 40. Therefore, sum = 495 + 491 + 40 = 1026.

Constraints:

• The number of nodes in the tree is in the range [1, 1000].
• 0 <= Node.val <= 9
• The depth of the tree will not exceed 10.

Solution

using LeetCodeNet.Com_github_leetcode;

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left;
 *     public TreeNode right;
 *     public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
public class Solution {
    private int sum = 0;

    public int SumNumbers(TreeNode root) {
        RecurseSum(root, 0);
        return sum;
    }

    private void RecurseSum(TreeNode node, int curNum) {
        if (node.left == null && node.right == null) {
            sum += 10 * curNum + node.val.Value;
        } else {
            if (node.left != null) {
                RecurseSum(node.left, 10 * curNum + node.val.Value);
            }
            if (node.right != null) {
                RecurseSum(node.right, 10 * curNum + node.val.Value);
            }
        }
    }
}

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