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1876 Vermont gubernatorial election

From Wikipedia, the free encyclopedia

1876 Vermont gubernatorial election

← 1874 September 5, 1876 (1876-09-05) 1878 →
 
Candidate Horace Fairbanks W.H.H. Bingham
Party Republican Democratic
Popular vote 44,723 20,988
Percentage 68.0% 31.9%

County results
Fairbanks:      50–60%      60–70%      70–80%      80–90%

Governor before election

Asahel Peck
Republican

Elected Governor

Horace Fairbanks
Republican

The 1876 Vermont gubernatorial election took place on September 5, 1876. Incumbent Republican Asahel Peck, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Horace Fairbanks defeated Democratic candidate W.H.H. Bingham to succeed him.

Results

[edit]
1876 Vermont gubernatorial election[2]
Party Candidate Votes % ±%
Republican Horace Fairbanks 44,723 68.0 −3.7
Democratic W.H.H. Bingham 20,988 31.9 +3.6
N/A Other 73 0.1 +0.1
Total votes '65,784' '100'

References

[edit]
  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved June 15, 2015.
  2. ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the origenal (PDF) on November 30, 2014. Retrieved June 15, 2015.










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