1836 United States presidential election in Kentucky
Appearance
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County Results
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Elections in Kentucky |
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Government |
The 1836 United States presidential election in Kentucky took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.
Results
[edit]United States presidential election in Kentucky, 1836[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | William Henry Harrison | 36,861 | 52.59% | 15 | |
Democratic | Martin Van Buren | 33,229 | 47.41% | 0 | |
Totals | 70,090 | 100.0% | 15 |
References
[edit]- ^ "1836 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved August 4, 2012.