задание по for готово #44
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skeapskeap
reviewed
Nov 27, 2023
for_challenges.py
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| for name in names: | ||
| if is_male[name] == False: |
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True, False, None в питоне являются синглтонами, поэтому сравнение с ними обычно делают через is вместо ==
if is_male[name] is False
for_challenges.py
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| # ??? | ||
| print(f'Всего {len(groups)} группы') | ||
| number_group = 1 | ||
| for number_persons in groups: |
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рабочее решение, но советую посмотреть на enumerate
for number_group, number_persons in enumerate(groups, start=1):
...
for_challenges.py
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| number_group = 1 | ||
| for names in groups: |
skeapskeap
approved these changes
Nov 27, 2023
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| for name in names: | ||
| if is_male[name] is False: |
There was a problem hiding this comment.
как бы ты разрулил случай, когда имя отсутствует в is_male ?
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Можно циклом for вытащить key, value. Так for key, value in is_male, а потом так же через if. Правильно понял вопрос?
| @@ -40,18 +45,25 @@ | |||
| ['Вася', 'Маша', 'Саша', 'Женя'], | |||
| ['Оля', 'Петя', 'Гриша'], | |||
| ] | |||
| # ??? | |||
| print(f'Всего {len(groups)} группы') | |||
| for index, name in enumerate(groups, start=1): | |||
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| for index, names in enumerate(groups, start=1): |
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| # Вывести количество гласных букв в слове | ||
| word = 'Архангельск' | ||
| # ??? | ||
| count = 0 | ||
| for i in word.lower(): |
| count_word = len(sentence.split()) |
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