W a t e r e x c e s s = 0.6 W ( 1 − [ N a + ] o b s 140 ) {\displaystyle Water\ excess=0.6\ W\left(1-{\frac {[Na^{+}]_{obs}}{140}}\right)}
W a t e r d e f i c i t = 0.6 W ( [ N a + ] o b s 140 − 1 ) {\displaystyle Water\ deficit=0.6\ W\left({\frac {[Na^{+}]_{obs}}{140}}-1\right)}